Tuesday, September 2, 2008

New Shots! New Hair!




I would like to thank Bench Fix Salon for my hair! 8D

21 comments:

  1. yessss...may ganung factor., hahaha., ayus!., :)

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  2. aba naman. haven't seen you in a while na. you're changing~~~~ :3 go go go denji-ness~ :3 (and you look nice. :3)

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  3. haha! ayos ayos! teka, diba ginto lang ang tinatanggap sa bench?
    kumusta naman ang 110.2 at bumubula na ang bibig ko kanina. explain mo naman kung bakit magiging equal ang column rank sa row rank. hindi ko talaga maconfirm. *watda, tama bang magmath dito*

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  4. what do you mean na ginto lang ang tinatanggap sa bench?

    saka ganito ung sa matrix rank:
    1.) reduce the matrix to REF form
    2.) count the rows with leading (non-zero) entries. that count was the row rank.
    3.) repeat #2, this time, with columns. that count will be the column rank.
    4.) by proof of ma'am dicuanco (aka, PMD) [ie, "obviously"], row rank is equal to column rank. that will now become the rank of the matrix

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  5. i mean... magkano haircut *winks*
    well, ang problema ko kasi ay kung pano yan igegeneralize. itatranspose muna bago iperform ang 2 for col rank.

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  6. ahh... parang david's lang din... 225 ung sa stylist ko. (inangkin?!)

    saka... panong transpose? pra mabilang mo ung column rank na para kang nagbibilang ng row rank?

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  7. 225 perfect square. *ano naman*
    uhemmm. ganun pagkakaintindi ko eh.

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  8. haha... i dunno if this will help pero ang gawin mo, mag GJE ka ng isang matrix, tapos bilugan mo lahat ng leading entries. 8D
    tapos bilangin mo ung circles row-wise and column-wise. sorry naman, bopols ako magturo. 8D

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  9. pero dapat equal yung number of circles di ba? *malamang* o sha sha. salamat salamat! gotta go. nice hair. hehe.

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  10. un na nga un, eh. there's no such thing as two leading entries in a row and in a column. kasi ladder. try mo pang himayin ung matrix mo, horizontally and vertically.

    haha, saka salamat din. :P

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